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	Database normalization - Wikipedia, the free encyclopedia
		It requires that there are no non-trivial functional dependencies of a non-key attribute on a part (subset) of a candidate key.
		In order to find if a table is in 2NF, ask whether any of the non-key attributes of the table could be derived from a subset of the composite key, rather than the whole composite key.
		Third normal form (3NF) requires that the table is in 2NF, and that there are no non-trivial functional dependencies of non-key attributes on something other than a superset of a candidate key.
	en.wikipedia.org /wiki/2NF (1963 words)

	Effects of Induction and Age-dependent Enzyme Expression on Lung Bioavailability, Metabolism, and DNA Binding of Urban ... (Site not responding. Last check: 2007-11-03)
		B[a]P was administered as a suspension with the carcinogen adsorbed onto UAP with the carcinogen dissolved in an artificial alveolar surfactant: dipalmitoyl phosphatidylcholine/phosphatidylglycerol (80:20, w/w) and 1 mg albumin/12 mg phospholipid.
		The lung metabolism of 2NF is induced by pretreatment of rats with BNF as observed in the isolated perfused and ventilated rat lung.
		The lung microsomal 2NF metabolism increased in parallel with the age-dependent up-regulation of lung P450IIB1.
	ehp.niehs.nih.gov /members/1994/Suppl-4/gotze-full.html (7215 words)

	Second Normal Form (2NF) (Site not responding. Last check: 2007-11-03)
		A relation is in 2NF if it is in 1NF and every non-key attribute is fully dependent on each candidate key of the relation.
		The concept of 2NF requires that all attributes that are not part of a candidate key be fully dependent on each candidate key.
		Higher level normalization is needed to resolve such problems with relations that are in 2NF and further normalization will result in decomposition of such relations.
	www.cs.jcu.edu.au /Subjects/cp1500/1998/Lecture_Notes/normalisation/2nf.html (319 words)

	[No title] (Site not responding. Last check: 2007-11-03)
		If you were to write down “A, C” then it is assumed that you think R has multiple keys where A is a key and C is a key of R, which is wrong.
		It not important that you mention a violation is specifically 2NF and therefore 3NF (although it helps in understanding your reasoning) but every violation of both must be mentioned as a 3NF violation when prompted for 3NF violations of a schema.
		As a recap, please note that R’s FD1 with the 2NF violation was such because it was a subset of the key of R. After decomposition, the key of R is still {A,C} but there is no functional dependency in R that has a 3NF violation.
	www.cs.fsu.edu /~cop4710/references/normalizationGuide.doc (2075 words)

	[No title]
		Converting a database format from 1NF to 2NF is very difficult and complicated.
		A table is in Second Normal Form (2NF) if it is in 1NF and it includes no partial dependencies.
		It is possible for a table in Second Normal Form (2NF) to exhibit transitive dependency, where one or more attributes may be functionally dependent on nonkey attributes.
	www.isy.vcu.edu /~ssamoilenko/normtest.doc (1038 words)

	Lecture 14 (Site not responding. Last check: 2007-11-03)
		The test for 2NF involves testing for functional dependencies whose left-hand side attributes are part of the primary key.
		If a relation schema is not in 2NF, it can be "second normalized" or "2NF normalized" into a number of 2NF relations in which nonprime attributes are associated only with the part of the primary key on which they are fully functionally dependent.
		According to Codd's original definition, a relation schema R is in 3NF if it satisfies 2NF and no nonprime attribute of R is transitively dependent on the primary key.
	carbon.cudenver.edu /~esbrowde/csc4287/lectures/lecture18.html (992 words)

	CS360-lecture18-spring (Site not responding. Last check: 2007-11-03)
		Definition of 3NF – A relation is in 3NF if it already is in 2NF and 1NF and no non-PK attribute is transitively dependent on the PK If transitive dependencies exist we break out those attributes into their own relation
		More general definitions of both 2NF and 3NF require that dependencies also be eliminated on candidate keys not just PK's
		Both 2NF and 3NF just deal with dpendencies on the PK – don't look at dependencies on other candidate keys
	www.cs.uidaho.edu /~ctaylor/CS360/CS360-lecture18-spring.html (1011 words)

	[No title]
		Here is the intuition behind 2NF, 3NF, BCNF as well as examples in which they differ...
		R(A1,A2,A3,A4,A5) A1,A2,A3->A4 A1,A2->A5 R is not in 2NF: Consider A1,A2->A5, the key for R is {A1,A2,A3} and part of the key {A1,A2} determines A5 (a non-key attribute).
		They keys for this relation are {PROPERTY_ID} or {COUNTY_NAME, LOT_NUM} or {AREA, LOT_NUM} Remember, 2NF means no FDs from part of a key to a non-key attribute.
	www.cs.toronto.edu /~arnold/343/04f/lectures/12 (353 words)

	Normalization
		A table is in 2NF if it is in 1NF and the partial dependencies are eliminated.
		The primary key of the new table (repeating group) is always a composite key; Usually document number and a field uniquely describing the repeating line, like an item number.
		We explore the three 2NF tables above for transitive dependencies (attribute depending on another attribute that is not a part of the primary key).
	www.ccsu.edu /business/faculty/petkovao/MIS515/MyNormalization.htm (720 words)

	Chapter 14 answers (Site not responding. Last check: 2007-11-03)
		Because it is not in 2NF, it is not in 3NF either.
		2NF: By simple observation, we can see that this relation is not in 2NF.
		Because by definition of 2NF, every non-prime attribute is not fully
	www.cc.gatech.edu /classes/AY2000/cs4400_spring/cs4400a/ch14ans.html (225 words)

	[No title]
		Group Member1: Group Member2: Note: Edit with a standard text editor (not word etc).
		We list all FDs above and whether they violate 2NF ABC->DEFGHIJ DE->ABCFGHIJ BC->E BC->F H->IJ G->B This can be fixed by converting to the following schema (I have included the week 12 lecture notes below for use as a template, please modify so that it applies to the assignment question.
		In the end, there should be no mention of the week 12 example.
	www.cs.toronto.edu /~arnold/343/04f/assignments/03/q1.txt (137 words)

	[No title]
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		If it is not in 2NF, give a lossless 2NF decomposition.
		If it is not in 2NF, give a lossless 2NF de composition.
	cse.unl.edu /~agnes/2nf_example.doc (156 words)

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