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| | Jay's Corner 5 |
 | | Similarly, if a position in the triangle with modulus 2 is fl, then the binomial coefficient is not evenly divided by 2 (that is, it is an odd number), and so it can not be evenly divided by 4 or 8 or any higher power of 2. |
 | | If a position in either of the "smaller" triangles is fl, then that position in the mod 6 triangle must be fl as well, since the binomial coefficient is either not divisible by 2 or by 3, and so, it can not be divisible by 6. |
 | | This means that if we took copies of the mod 2 triangle and the mod 3 triangle and placed one on top of the other, the only white squares that appear are those where the corresponding binomial coefficient is divisible by both 2 and 3, i.e., by 6. |
| www-math.cudenver.edu /~wcherowi/jcorn5.html (2042 words) |
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