| | ORGANIC CHEMISTRY I (Site not responding. Last check: 2007-11-07) |
 | | The rate-determining step will thus be the formation of the carbocation, and since the leaving group, chloride, is the same for both compounds, the stability of the carbocation formed will determine the rate of reaction. |
 | | The carbocation formed when the iodide falls off is planar (the C+ is sp2 hybridized), and can be attacked from either side by the nucleophile. |
 | | Since the formation of the carbocation from the alkyl halide is an endothermic process, the more stable isomer of starting material will have a larger energy hill to climb to get to the same place, so it will react slower. |
| www.muhlenberg.edu /depts/chemistry/COURSES/ORGANIC/RUSSELL/201/opa110904a.htm (1503 words) |