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| | Math Forum - Ask Dr. Math (Site not responding. Last check: 2007-10-20) |
 | | Date: 12/19/2000 at 13:12:04 From: Doctor Mitteldorf Subject: Re: Complex Analysis: Integrals Dear Lydia, The rule is to evaluate the function at each of the poles contained within the contour of integration, then multiply by 2pi*i. |
 | | I got that the integral of (z^2/(z+1))/(z-1)^2, which is the same as the original integral, is equal to 2pi*i (-1/(i+1)), which comes to 2pi*i (-1/2+(1/2)i) or ((-pi*i) - pi). |
 | | Use the fact that the loop integral of z^n is identically zero for every value of n, positive or negative, except n = -1. |
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