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 | | p(v)=(6-v)(-1-v)-(3)(-4)=v^2-5v+6=(v-2)(v-3) ==> eigenvalues are {2,3} A-2I = 4 -4 ==> eigenspace of v=2 3 -3 is Span{(1,1)'} A-3I = 3 -4 ==> eigenspace of v=3 3 -4 is Span{(4,3)'} g. |
 | | A-1I = 0 1 1 ==> eigenspace of v=1 0 1 1 is Span{(1,0,0)',(0,1,-1)'} 0 0 0 A-2I = -1 1 1 ==> eigenspace of v=2 0 0 1 is Span{(1,1,0)'} 0 0 -1 i. |
 | | A-0I = 4 -5 1 ==> eigenspace of v=0 1 0 -1 is Span{(1,1,1)'} 0 1 -1 A-1I = 3 -5 1 ==> eigenspace of v=1 1 -1 -1 is Span{(3,2,1)'} 0 1 -2 A-2I = 2 -5 1 ==> eigenspace of v=2 1 -2 -1 is Span{(7,3,1)'} 0 1 -3 k. |
| www.math.wustl.edu /~victor/classes/ma309/s09.txt (1273 words) |
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