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| | Ptolemy's Tetrabiblos: Book the Third: Chapter XV. Exemplification |
 | | Now, since the first point of Aries is distant six temporal hours from the mid-heaven above the earth, the times of that distance will be found, by multiplying the said six hours by the seventeen equatorial times of the horary magnitude of the first point of Gemini, to be 102. |
 | | Now, as it is required to bring the first point of Gemini, in its second position, to the mid-heaven, the whole distance is to be reckoned, viz. |
 | | And the first point of Gemini, on arriving at the ascendant, will be distant from the mid-heaven 102° 39' by right ascension; the 13th degree of Aquarius being then in culmination in the prescribed latitude. |
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