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| | 6.3.html |
 | | Applying the Gram-Schmidt process, we let v_1 = [1, 1, 1] and compute [1, 0, 1] - (1 + 0 + 1)/(1 + 1 + 1) [1, 1, 1] = [1, 0, 1] - (2/3)[1, 1, 1] = [1/3, -2/3, 1/3] and take v_2 = [1, -2, 1]. |
 | | Applying the Gram-Schmidt process, let v_1 = a = [1, 1, 1], and a_2 = e_1, and we get a_2 - (a_2*v_1)/(v_1*v_1) v_1 = [2/3, -1/3, -1/3] so we take v_2 = [2, -1, -1]. |
 | | Again we apply the Gram-Schmidt process, letting v_1 = [1, -1, 1, 0, 0]. |
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