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| | The Greedy Algorithm for Unit Fractions) |
 | | If we apply the "greedy algorithm", which consists of taking the largest qualifying unit fraction at each stage, we would begin with the term 1/3, leaving a remainder of 1/3. |
 | | So,the odd greedy expansion of 2/3 terminates after four steps, giving the result 2/3 = 1/3 + 1/5 + 1/9 + 1/45 The non-zero remainders we encountered during this process were 1/3, 2/15, and 1/45, with the numerators 1, 2, 1. |
 | | This is not a trivial question, as shown by the odd greedy expansion of 1 (not using 1/1 on the first step). |
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