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| | Math Forum - Ask Dr. Math |
 | | For example, find the Jordan Canonical Form of: A = [(3 1 2),(0 3 0),(0 0 3)] I approached the problem by finding [lambda I-A]. |
 | | Date: 04/29/98 at 11:21:32 From: Doctor Rob Subject: Re: Jordan Canonical Form First you need to find the elementary divisors of A. They will be divisors of the minimal polynomial. |
 | | The matrix S then should be: S = [(0 0 1),(-2 1 3),(1 0 0)] S^(-1) = [(0 0 1),(-3 1 2),(1 0 0)] S^(-1)*A*S = [(3 0 0),(0 0 -9),(0 1 6)] To convert this into Jordan Form, the first basis element can remain the same, but the last two must change. |
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