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| | [No title] (Site not responding. Last check: 2007-10-21) |
 | | That is [ 0, 11, 24, 65, 90, 129, 173, 212, 237, 278, 291, 302 ] = [ 3, 5, 30, 57, 104, 116, 186, 198, 245, 272, 297, 299 ] It means 0^k+11^k+24^k+65^k+90^k+129^k+173^k+212^k+237^k+278^k+291^k+302^k = 3^k+5^k+30^k+57^k+104^k+116^k+186^k+198^k+245^k+272^k+297^k+299^k (k=1,2,3,4,5,6,7,8,9,10,11) It is a great progress of the Prouhet-Tarry-Escott problem. |
 | | An ideal solution is one with only k + 1 terms on each side. |
 | | Prouhet's general result (early >1850's) has k arbitrarily large.Allan Adler To the System a1^k+a2^k+...+am^k=b1^k+b2^k+...+bm^k (k=1,2,...n) Prouhet's general result is that there are m=2^n numbers on the left side, and m=2^k numbers on the righr side. |
| www.math.niu.edu /~rusin/known-math/99/tarry_escott (549 words) |
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