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Topic: KJ mol


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In the News (Wed 23 Dec 09)

  
  Topic E Additional Problem Answers
Burning 1 mole of C produces 393.5 kJ, so we can set up a proportionality: we find that we need 32,693 moles of C. This equals 393,000 grams, or 393 kilograms.
H value for the balanced equation in the problem" (which uses 1 mol of ZrC), the answer is -1301 kJ.
We used 0.019373 mol of NH and 0.0100 mol of H
www.ccsf.edu /Departments/Chemistry/chem101a/topcsol/topic_e_ans.htm   (672 words)

  
 Photopolymerizable compositions containing aminoaryl ketone photoinitiators - US Patent 5145885   (Site not responding. Last check: 2007-10-22)
15.08 g (0.06 mol) of 1-(4-fluorophenyl)-2-methyl-2-morpholinopropan-1-one and 5.23 g (0.06 mol) of morpholine are dissolved in 25 ml of dimethyl sulfoxide, and the solution is heated to 160° C. together with 8.3 g (0.05 mol) of potassium carbonate.
13.2 g (0.05 mol) of 1-(4-fluorophenyl)-2-methyl-2-(4-methylpiperazino)-propan-1-one and 6.5 g (0.065 mol) of 1-methylpiperazine are dissolved in 20 ml of dimethyl sulfoxide, and the solution is heated to about 115° C. together with 6.9 g (0.05 mol) of potassium carbonate.
49.86 (0.30 mol) of 1-(4-fluorophenyl)-2-methylpropan-1-one, prepared by a Friedel-Crafts reaction from isobutyryl chloride with fluorobenzene analogously to European Patent Application No. 3,002, and 25.5 g (0.30 mol) of piperidine are dissolved in 120 ml of dimethyl sulfoxide, and the solution is heated to 110° C. together with 41.5 g (0.30 mol) of potassium carbonate.
www.patentstorm.us /patents/5145885.html   (4698 words)

  
 Problem Set 2   (Site not responding. Last check: 2007-10-22)
C: Decomposition of one mole of N2O5 produces 2.5 mol of gas, which performs work on the surroundings.
C? b)         In metabolism, oxidation of 1 mol glucose results in the conversion of (about) 38 mol ADP to ATP.
mol of glucose from the medium into the cell at 37
home.austin.rr.com /mikeready/ProblemSet2.htm   (617 words)

  
 Exercise4   (Site not responding. Last check: 2007-10-22)
Object A has the greater heat capacity since it raised the temperature of the same mass of water more than did object B. The masses of the objects are unknown, so specific heats cannot be calculated, or even compared qualitatively.
Heat lost by the water as it cools is gained by the "process" of the ammonium nitrate dissolving.
answer is +155.7 kJ - Reverse the second reaction (change the sign), and divide the second and third reactions by 2, then add.
home.nc.rr.com /jyouker1/Exercise5.html   (339 words)

  
 THI4 - Thiazole biosynthetic enzyme, mitochondrial precursor   (Site not responding. Last check: 2007-10-22)
The dissociation constant for the RNase A-RI complex increased from 74 fM (RNase A) to 4.5 pM (Lys-1, Cys-7-methyl RNase), corresponding to a decrease in binding energy of 10 kJ mol-1.
At 25 degreesC, the average binding enthalpy for a scFv fragment was favorable (-61 kJ mol-1), the entropy change was unfavorable, and the change in heat capacity was -1.27 +/-0.14 kJ mol-1 K-1.
It was observed that the apparent values of both Lpg and ELp increase with cooling rate, from Lpg = 0.0116 micrometer 3 micrometers-2 atm-1 min-1 and ELp = 19.4 kJ mol-1 for 9 degrees K/min to Lpg = 2.11 micrometers 3 micrometer-2 atm-1 min-1 and ELp = 101 kJ mol-1 for 35 degrees K/min.
www.pdg.cnb.uam.es /UniPub/iHOP/gg/33347.html   (417 words)

  
 00lecture26
There is a table of these enthalpies for may common substances in the appendices of your text.
H for combustion of methane as -890.3 kJ.
In the body, the metabolism of simple sugar is, overall, the same reaction, although it takes over 25 steps when done biochemically.
www.chem.neu.edu /Courses/1111Tom/00lecture26.html   (508 words)

  
 Take a Quiz
What is the entropy for the vaporization of 225 g of ethanol, CH3CH2OH, at its boiling point of 78 degrees C? The DHvap for ethanol is 39.3 kJ mol^1.
DH^o = -95.0 kJ and DS^o = -123 J/K As the temperature is increased for this reaction
c) The reaction is exothermic, and the catalyst reduces Ea by 15 kJ mol-1.
www.chem.lsu.edu /lucid/butler/1202/1202t2.html   (838 words)

  
 Chemical Energy
When 1.0 mol or 22.4 L of CH, at 273K and 1 atm, is oxidized completely, the standard enthalpy change is 890.4 kJ.
One cubic meter is 1000 L (/22.4 = 44.6 mol).
Standard enthalpies of formation and standard entropies are important thermodynamic data, and this link gives an extensive table of values for some key compounds.
www.science.uwaterloo.ca /~cchieh/cact/c120/chemener.html   (1777 words)

  
 Take a Quiz
Assume 150 L (~40 gallons, 8260 mol H2O) of water and a temperature rise of 40 degrees C (typically, input water at about 65 degrees F, and the set point is ~135 degrees F).
The molar heat capacity of water is 75.3 J mol^1 K^1.
Based on the energy level diagram shown below, what is the change in enthalpy for the reaction of 1 mol ethane with 7/2 mol oxygen.
www.chem.lsu.edu /lucid/butler/1202/1202t1.html   (822 words)

  
 Help With Homework 1   (Site not responding. Last check: 2007-10-22)
Use the molar heat of vaporization in Table 11.1 to calculate the heat release for 2.83 mol C
In Calculation 1, the heat is negative because the combustion is exothermic (releases heat).
We find that 52.4 kJ of heat is required for each mole of aniline we want to vaporize.
www.accd.edu /pac/chemistr/spring00/hwk01hlp.htm   (472 words)

  
 Mol-Iron Information and Resources Online at The Drug Database - Find Useful Articles and Websites on Mol-Iron Right ...
with that of gadopentetate dimeglumine at 40 µmol iron per kilogram for first-pass investigations, with prolonged...
The relation between mol compound A and mol compound B is from a chemical reaction rather than the...
to 215 µmol (12 mg) of iron per liter at standard...
www.thedrugdatabase.com /directory/M/Mol-Iron   (318 words)

  
 Lecture VL 23/24:   (Site not responding. Last check: 2007-10-22)
You must multiply the enthalpies by the coefficients in the equation.
OH = 500 g/(46.0 g/mol) = 10.9 mol; 1368 kJ/mol · 10.9 mol = 14.9 · 10
Because the temperature of the calorimeter rises, heat is given off in the reaction.
www.tu-cottbus.de /BTU/Fak1/AnorgCh/2324Answers.htm   (300 words)

  
 General Chemistry II   (Site not responding. Last check: 2007-10-22)
moles Na = 3650 g *(1 mol / 77.97834 g) = 46.8 mol Na 2 mol Na react with 2 mol CO – it is a 1 to 1 relationship
46.8 mol Na react with 46.8 mol CO from previous problem 8.70 mol of CO is breathed in 24 hrs.
Dry ice would not make a good ice skating surface because when increased pressure is applied dry ice remains a solid.
carbon.cudenver.edu /~jburmeis/exam4/chem1exam4(key).html   (929 words)

  
 [No title]
kJ/mol = -5.74 kJ/g[(84 g/1 mol)] = -492 kJ/mol 6.
[(1 mol/106.8 g)(-84.5 kJ/1 mol)] = 1.09 kJ 9.
moles silver nitrate = (moles silver chromate)*[conversion factor(s)] (Molarity)(Vol.in L) = (mass/FW)[(2 mol sn/1 mol sc)] (0.84)(Vol.in L) = (1.00 g/(194 g/mol sc))[2 mol sn/1 mol sc] Vol.in L = 12.27 mL 13.
www.luc.edu /faculty/spavko1/exam-s/a-5.htm   (513 words)

  
 Chemistry 1051 - Exam 2 - November 6, 1995   (Site not responding. Last check: 2007-10-22)
What is the energy in kJ of a mole of photons of infrared radiation of wavelength [lambda] = 1.72 x 10
The temperature of the solutions before mixing was 22.50 deg.C and it rises to 24.28 deg.C after mixing.
How much heat in kJ will be evolved during the combustion of 16.0 g of C
www.chem.umn.edu /class/1051/old/winter/OldExam2.html   (1403 words)

  
 Strengths of Covalent Bonds   (Site not responding. Last check: 2007-10-22)
Example: The reaction between 1 mol of chlorine and 1 mol methane
Bonds broken: 1 mol of Cl-Cl bonds, 1 mol of C-H bonds
[242 kJ + 413 kJ] - [431 kJ + 328 kJ]
wine1.sb.fsu.edu /chm1045/notes/Bonding/Strength/Bond09.htm   (320 words)

  
 Chapter 6 HomeworkChapter 6 Homework   (Site not responding. Last check: 2007-10-22)
For a particular process q = -17 kJ and w = +21 kJ.
  When 0.500 mole sulfur is reacted, 148 kJ of energy are released.
The heat associated with a chemical reaction is measured in a device called
www.puc.edu /Faculty/David_Duran/chem111homework6.htm   (326 words)

  
 CHEMISTRY 115
The sign is actually negative because energy is released when bonds are formed; the phrasing of the question could permit a + sign since it asking for the energy released.
= -52.284 kJ + 2304.9 = +2252.6 KJ Or for the atomization reaction: [4(C- H) + C=C] = 4(412) + [C=C] = (+2252.6 kJ) = 1648 kJ + [C=C] [C=C] = 2252.6 – 1648 = 604.6 kJ = 605 kJ
A Cu2+(aq) solution is electrolyzed using a current of 0.500 A. Calculate the mass of Cu that would be plated out after 500 min.
condor.depaul.edu /~smelford/Chem115/hw401ans.htm   (627 words)

  
 Chemistry : Chapter 13 : Heat of Solution   (Site not responding. Last check: 2007-10-22)
H value is per moles solute, not per mol solution.
H is positive for endothermic dissolutions(temperature decreases) and negative for exothermic dissolutions (temperature increase).
The heat of solution will be positive because the temperature of the solution decreased.
www.wwnorton.com /chemistry/concepts/chapter13/ch13_1.htm   (651 words)

  
 Untitled Document
(-1652 kJ/2 mol prod) (1 mol Fe/55.85 g/mol) 275.
(-1652 kJ/2 mol prod) = (-4000 kJ/x mol prod)
2.00 mol oxygen would yield 0.0417 mol prod.
www.d.umn.edu /~btsai/Chem1151s01/assignmar26.htm   (559 words)

  
 Chem 111 Exam 3 Answer Key Fall 1995   (Site not responding. Last check: 2007-10-22)
An ideal gas at 10 atm pressure in a flask of 5.0 l volume is allowed to expand into a vacuum where the final volume is 10.0 l.
If 0.500 mol neon at 1.00 atm pressure and 273 K expands against a constant external pressure of 0.100 atm until the gas pressure reaches 0.200 atm and the temperature reaches 210 K, calculate each of the following in joules.
Calculate delta G(0) and Keq at 298 K for this reaction.
www.rice.edu /projects/colleges/sid/tests/CHEM111/fall-1995/exam3.html   (1138 words)

  
 Catalogo Articoli   (Site not responding. Last check: 2007-10-22)
A detailed study was undertaken to characterize the deformation behavior of a superplastic 3 mol% yttria-stabilized tetragonal zirconia (3YTZ) over a wide range of strain rates, temperatures and grain sizes.
The activation energy was similar for both regions with a value of similar to 550 kJ mol(-1).
Microstructural measurements revealed that grains remained essentially equiaxed after the accumulation of large strains, and very limited concurrent grain growths occurred in most experiments.
serials.cib.unibo.it /cgi-ser/start/it/spogli/df-s.tcl?prog_art=485659&language=ITALIANO&view=articoli   (330 words)

  
 Exam 3 2004
(-0.50 kJ)(3 mol/-138.4 kJ) (46 g/mol) = 0.5 g (50.0g/63.0g/mol) x (-138.4 kJ/2 mol) = -55 kJ
delH = 33.9 kJ since the pressure is constant.
Entropy decreases when 3 mol of gas --> 2 mols of gas.
www.d.umn.edu /~btsai/Chem1151s04/exam3solns.htm   (492 words)

  
 Whikehart, Mol Vis 3:3, 1997
The energies of stabilization for the docking processes were obtained based on the summation and kinds of bonds produced.
In the case of docking to the phosphatidyl-choline head group region, correction was made for the hydrocarbons extending into the aqueous environment by subtracting the appropriate destabilizing energies of 6 kJ per carbon for the carbons extending into that region (1).
The table indicates that binding of 12 (R) HETE and 8 (R) HHDTrE to phosphatidyl choline in the upper fatty acid regions are the most favored by ~1.6 to 1 over binding to the enzyme and by more than eight fold over binding to the head group region.
www.molvis.org /molvis/v3/a3   (3378 words)

  
 Chem 1A Homework #3   (Site not responding. Last check: 2007-10-22)
In the following equation, each tabular value is multiplied by the number of moles of bonds formed (or number of moles of gaseous atoms formed by atmoization).
)] - [3 * (2 * 728 kJ mol
Adding heat will not shift the equilibrium very far to the left since there is basically no enthalpy change.
www.cchem.berkeley.edu /~chem1a/fall96/hmwk/hmwk3.html   (1142 words)

  
 Chapter 1-7 Exam Dr
OH(l) (Molar mass = 46.07 g/mol), is –1368 kJ · mol
The standard enthalpy of formation of CO(g) is –110.5 kJ · mol
a) 10.0 mol b) 3.33 mol c) 0.300 mol d) 1.67 mol e) 7.50 mol
www.lssu.edu /academics/arts_letters_ss/education/myton/ch115/115test3.htm   (692 words)

  
 Mechanisms for the hepatic uptake of organic cations. Studies with the muscle relaxant vecuronium in isolated rat ...
Studies with the muscle relaxant vecuronium in isolated rat hepatocytes -- Mol et al.
Articles by Mol, W. Articles by Meijer, D. Mechanisms for the hepatic uptake of organic cations.
WE Mol, GN Fokkema, B Weert and DK Meijer
jpet.aspetjournals.org /cgi/content/abstract/244/1/268   (527 words)

  
 Ansers to 2 nd sample test Gen Chem
12.01 g/mol = 3.142 mol reduce ratio to 1.666 *3 = 5
1.008 g/mol = 5.615 mol 2.9776 *3 = 9
g/mol = 1.886 mol 1 *3 = 3
www.clscc.cc.tn.us /courses/erowlee/t2a_s_10.html   (347 words)

  
 Chemistry, Second Edition Chapter 17 -- Practice Exercise II   (Site not responding. Last check: 2007-10-22)
CH CHCl(g) + HCl(g) at 25°C? (standard free-energy change = 36.2 kJ)
What is the standard free-energy change (in kJ) at 25°C for the reaction FeS(s) + 2H
Note: answer choices in this exercise are randomized.
cwx.prenhall.com /mcmurry/chapter17/multiple1/deluxe-content.html   (413 words)

  
 Practice Questions: Thermodynamics
The standard enthalpy of reaction is -284 kJ and the standard entropy of reaction is -87 J/K. Estimate the temperature at which the equilibrium begins to favor the decomposition of CO Assume that the enthalpy and the entropy of reaction are not affected by temperature.
From the indicated standard entropies given in J/K, please calculate the standard entropy of reaction for:
-32.734 kJ ; proceed to the right; 5.3x10
www.towson.edu /users/debye/chem111/practice/111thermo.html   (317 words)

  
 Physical Chemistry 4:131 T.A. Help Site Fall '99 Chapter 2 Exercises
U = 1.247 kJ; q = 1.247 kJ; w = 0; p
=11.8 L (Book values the same) Pretty straight ahead, but remember to take into account n= 0.5 mol.
H cyclopropane to propene = -33 kJ mol
www.uiowa.edu /~c004131a/Drew4131/ChapterTwoExerciseHelpPage.html   (468 words)

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