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 | | As we can see all the elements {1,
,12} are partition into triples, every element appears in a block once, and the sum of 1+5=6, 2+8=10, 4+7=11, and 3+9=12 so we have a Skolem triple system of order 4 and hence yield a cyclic STS(25). |
 | | Note that, if k=1, we omit those triples defined for 1£r£k-1; the remaining triples are {1,11,12}, {3,5,8}, {2,7,9}, and {4,6,10} which form a Skolem triple system of order 4 different from the one in example 8a. |
 | | Note that, if k=1, we omit those triples defined for 1£r£k-1; the remaining triples are {1,14,15}, {3,6,9}, {5,8,13}, {2,10,12}, and {4,7,11} which form a Skolem triple system of order 5 different from the one in example 8b. |
| courses.csusm.edu /math540ak/STS.doc (2133 words) |
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