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| | Tuning-Math Archive Section 3: 2100 - 2124 |
 | | Then the wedge product h^g = [u1,u2,u3,u4]^[v1,v2,v3,v4] is defined as: [u1*[v2,v3,v4]-v1*[u2,u3,u4], [u2,u3,u4] X [v2,v3,v4]] Written out in full, this is h^g = [u1*v2-v1*u2,u1*v3-v1*u3,u1*v4-v1*u4,u3*v4-v3*u4, u4*v2-v4*u2,u2*v3-v2*u3] Note that the first three elements of the wedge invariant, defined from any starting place, gives the mapping to primes of the non- octave generator of the pair of generators. |
 | | The triple wedge product of three 7-limit intervals is the val we get by putting the three intervals in as rows of a 4x4 matrix and making the top row the four basis vectors. |
 | | The wedge product of two intervals will be in a space of dimension n choose 2 = n(n-1)/2, and the length of the vector in the ordinary norm will be the area of the paralleogram defined by the two intervals, and the direction will be defined by the orientation of the paralleogram. |
| www.robertinventor.com /tuning-math/s___3/msg_2100-2124.html (5523 words) |
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